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The total inductance, L, is found by taking the reciprocal of the number you get for 1/L. Again, as with inductances in series, it s important to remember that all the units have to agree. Don t mix microhenrys with millihenrys, or henrys with nanohenrys. The units you use for the individual component values will be the units you get for the final answer.

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Problem 10-2 Imagine three inductors, with no mutual inductance, with values of 20.0 mH, 55.0 H, and 400 nH. What is the total inductance, in millihenrys, of these components if they are connected in series as shown in Fig. 10-3 First, convert all the inductances to the same units. Microhenrys are a good choice because that unit makes the calculation process the least messy. Call L1 = 20.0 mH = 20,000 H, L2 = 55.0 H, and L3 = 400 nH = 0.400 H. The total inductance is therefore L = 20,000 + 55.0 + 0.400 = 20,055.4 H. This is 20.1 mH after converting and rounding off.

Problem 10-3

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Suppose there are three inductors, each with a value of 40 H, connected in parallel with no mutual inductance, as shown in Fig. 10-4. What is the net inductance of the set

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10-4

Refer to the text in this chapter if necessary. A good score is at least 18 correct answers out of these 20 questions. The answers are listed in the back of this book. 1. The atomic number of an element is determined by (a) the number of neutrons. (b) the number of protons. (c) the number of neutrons plus the number of protons. (d) the number of electrons. 2. The atomic weight of an element is approximately determined by (a) the number of neutrons. (b) the number of protons. (c) the number of neutrons plus the number of protons. (d) the number of electrons. 3. Suppose there is an atom of oxygen, containing eight protons and eight neutrons in the nucleus, and two neutrons are added to the nucleus. What is the resulting atomic weight (a) 8 (b) 10 (c) 16 (d) 18 4. An ion (a) is electrically neutral. (b) has positive electric charge. (c) has negative electric charge. (d) can have either a positive or negative charge. 5. An isotope (a) is electrically neutral. (b) has positive electric charge. (c) has negative electric charge. (d) can have either a positive or negative charge.

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Call the inductances L1 40 H, L2 40 H, and L3 40 H. Use the formula above to obtain 1/L 1/40 1/40 1/40 3/40 0.075. Then L 1/0.075 13.333 H. This should be rounded off to 13 H, because the original inductances are specified to only two significant digits.

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