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string[] names = { "John", "Paul", "George", "Pete" }; XElement xNames = new XElement("Beatles", from n in names select new XElement("Name", n)); names[3] = "Ringo"; Console.WriteLine(xNames); Before discussing the results of this code, we want to point out just how cool this example is. Notice that we are creating an element whose name is Beatles and whose content is a sequence of XElement objects whose element is named Name. This code produces the following XML tree: <Beatles> <Name>John</Name> <Name>Paul</Name> <Name>George</Name> <Name>Pete</Name> </Beatles> That is pretty awesome. Each XElement object from the sequence becomes a child element. How cool is that As we mentioned, notice that even though we changed names[3] to "Ringo" prior to outputting the XML, the last element still contains Pete, the original value. This is because the names sequence has to be enumerated in order to construct the XElement object, thereby immediately executing the query. If we do indeed want the XML tree construction deferred, we need another way to do this, and that is exactly what streaming elements are for. With LINQ to XML, a streaming element is implemented with the XStreamingElement class. So, Listing 7-32 shows the same example, except this time we will use XStreamingElement objects instead of XElement objects.

if (isValueReference(value)) { component.setValueBinding(attrName, createValueBinding(value)); } else { component.getAttributes().put(attrName, value); } } You can use this setStringProperty() method to assign any component attribute that can take either a static value or a value binding (for example, #{sample.Date}). If the value is null, then you avoid explicitly storing the value in the component. To check whether the value is a JSF EL expression, you can use a method called isValueReference(). This method is provided by the UIComponentTag class and will return true if the specified value conforms to the syntax requirements of a value-binding expression. When the string is a valid value-binding expression, you create and store a corresponding ValueBinding instance as the attribute value.

Listin g 7-32. Demonstrating the Deferred Execution of the XML Tree Construction by Using the XStreamingElement Class

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With LINQ to XML, you can perform XML transformations using two completely different approaches. The first approach is to use XSLT via the bridge classes, XmlReader and XmlWriter. The second approach is to use LINQ to XML to perform the transformation itself by functionally constructing the target XML document and embedding a LINQ to XML query on the source XML document. Using XSLT provides the benefit that it is a standard XML technology. Tools already exist to assist with writing, debugging, and testing XSLT transformations. Additionally, because it already exists, you may have XSLT documents and can leverage them in new code using LINQ to XML. There is a world full of existing XSLT documents from which to choose. Additionally, using XSLT for your

string[] names = { "John", "Paul", "George", "Pete" }; XStreamingElement xNames = new XStreamingElement("Beatles", from n in names select new XStreamingElement("Name", n)); names[3] = "Ringo"; Console.WriteLine(xNames); If this works as we have explained, the last Name node s value will now be Ringo and not Pete. But the proof is in the pudding: <Beatles> <Name>John</Name> <Name>Paul</Name> <Name>George</Name> <Name>Ringo</Name> </Beatles> Sorry, Pete, it looks like you have been replaced yet again.

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