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USE tempdb; GO IF OBJECT_ID('dbo.Groups') IS NOT NULL DROP TABLE dbo.Groups; GO CREATE TABLE dbo.Groups ( groupid VARCHAR(10) NOT NULL, memberid INT NOT NULL, string VARCHAR(10) NOT NULL, val INT NOT NULL, PRIMARY KEY (groupid, memberid) ); INSERT INTO dbo.Groups(groupid, VALUES('a', 3, 'stra1', 6); INSERT INTO dbo.Groups(groupid, VALUES('a', 9, 'stra2', 7); INSERT INTO dbo.Groups(groupid, VALUES('b', 2, 'strb1', 3); INSERT INTO dbo.Groups(groupid, VALUES('b', 4, 'strb2', 7); INSERT INTO dbo.Groups(groupid, VALUES('b', 5, 'strb3', 3); INSERT INTO dbo.Groups(groupid, VALUES('b', 9, 'strb4', 11); INSERT INTO dbo.Groups(groupid, VALUES('c', 3, 'strc1', 8); INSERT INTO dbo.Groups(groupid, VALUES('c', 7, 'strc2', 10); INSERT INTO dbo.Groups(groupid, VALUES('c', 9, 'strc3', 12); GO memberid, string, val) memberid, string, val) memberid, string, val) memberid, string, val) memberid, string, val) memberid, string, val) memberid, string, val) memberid, string, val) memberid, string, val)

Figure 6.1 Using depth of field to focus attention on the subject. Use the rule of thirds. The rule of thirds is a guideline used by photographers that is also applicable to shooting video. Basically, according to the rule of thirds, your subject should not appear directly in the middle of the frame. To establish where the subject should be positioned in the frame, the frame should be divided into thirds, with two horizontal lines and two vertical lines. The subject should then be framed at one of the four points where the lines intersect. Figure 6.2 shows a frame divided using the rule of thirds.

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Remember that median is the middle value (assuming a sorted list) when the group has an odd number of elements, and it's the average of the two middle values when it has an even number. It's always a good idea to handle each case separately, and then try to figure out whether the solutions can be merged. So first, assume there's an odd number of elements. You can use a TOP(50) PERCENT query to access the first half of the elements, including the middle one. Remember that the PERCENT option rounds up. Then simply query the maximum value from the returned result set. Now handle the even case. The same query you use to get the middle value from an odd number of rows will produce the largest value of the first half of an even number of rows. You can then write a similar query to return the smallest value of the second half. Sum the two values, divide by two, and you have the median in the even case. Now try to figure out whether the two solutions can be merged. Interestingly, running the solution for the even case against an odd number of elements yields the correct result, because both subqueries used in the even case solution will end up returning the same row when there is an odd number of rows. The average of two values that are equal is obviously the same value. Here's what the solution looks like when you want to return the median of the val column for the

whole table: SELECT ((SELECT MAX(val) FROM (SELECT TOP(50) PERCENT val FROM dbo.Groups ORDER BY val) AS M1) + (SELECT MIN(val) FROM (SELECT TOP(50) PERCENT val FROM dbo.Groups ORDER BY val DESC) AS M2)) /2. AS median;

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For more information about weak references, see Weak References on MSDN: http://msdn.microsoft.com/en-us/library/ms404247.aspx. To access web resources more easily, see the online version of the bibliography on MSDN: http://msdn.microsoft.com/en-us/library/gg405487(PandP.40).aspx.

To return the median for each group, you need an outer query that groups the data by groupid. For each group, you invoke the calculation of the median in a subquery like so: SELECT groupid, ((SELECT MAX(val) FROM (SELECT TOP(50) PERCENT val FROM dbo.Groups AS H1 WHERE H1.groupid = G.groupid ORDER BY val) AS M1) + (SELECT MIN(val) FROM (SELECT TOP(50) PERCENT val FROM dbo.Groups AS H2 WHERE H2.groupid = G.groupid ORDER BY val DESC) AS M2)) /2. AS median FROM dbo.Groups AS G GROUP BY groupid;

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This query works in SQL Server 2000 with two small modifications: first, you must write TOP 50 PERCENT instead of TOP(50) PERCENT, and second, to work around an unexpected behavior of queries that use GROUP BY together with subqueries, you must use SELECT DISTINCT instead of GROUP BY to produce just one result row per group. Here is the solution for SQL Server 2000: SELECT DISTINCT groupid, ((SELECT MAX(val) FROM (SELECT TOP 50 PERCENT val FROM dbo.Groups AS H1 WHERE H1.groupid = G.groupid ORDER BY val) AS M1) + (SELECT MIN(val) FROM (SELECT TOP 50 PERCENT val FROM dbo.Groups AS H2 WHERE H2.groupid = G.groupid ORDER BY val DESC) AS M2)) /2. AS median FROM dbo.Groups AS G;

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