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public class UCConnectionMetaData implements ManagedConnectionMetaData { private UCManagedConnection mc; public UCConnectionMetaData(UCManagedConnection mc) { System.out.println("We are executing UCConnectionMetaData.constructor"); this.mc = mc; } public String getEISProductName() throws ResourceException { System.out.println("We are executing UCConnectionMetaData.getEISProductName"); return "ucnyjca"; } public String getEISProductVersion() throws ResourceException { System.out.println("We are executing

(2.2)

Figure 4 9. We want to open Interface Builder, so click on your nib file. 17. We need to have some wallpaper of your image that lies underneath all

UCConnectionMetaData.getEISProductVersion"); return "1.0"; } public int getMaxConnections() throws ResourceException { System.out.println("We are executing UCConnectionMetaData.getMaxConnections"); return 5; } public String getUserName() throws ResourceException { return mc.getUserName(); } }

More compactly, we can write = ( , + , + , + ). Generalizing to D-dimensional Minkowski space-time, we simply associate a plus sign with products of spatial coordinates. So the Lorentz invariant length squared of a vector is ( X )2 = X X = ( X 0 )2 + ( X 1 )2 + In nitesimal lengths or distances are described by ds 2 = dX dX = ( dX 0 )2 ( dX 1 )2 ( dX d )2 (2.4) + ( X d )2 (2.3)

The UCConnection class represents the handle to the underlying physical connection to the EIS. UCConnection is one of the few classes that does not implement an interface in the JCA specification. The implementation that follows is simple, but a working implementation might contain connectivity code using sockets, as well as other functionality:

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We include the minus sign out in front of the metric in Eq. (2.4) to ensure that ds = dX dX is real for timelike trajectories. With these notations in hand, we are ready to describe the trajectory of a free relativistic particle using the action principle. The action principle tells us that the relativistic motion of a free particle is proportional to the invariant length of the particles trajectory. That is, S = ds First let s gure out what the constant of proportionality is. EXAMPLE 2.1 Given that the action of a free, non-relativistic particle is S0 = dt (1/2)mv 2, where m is the mass of the particle and v is the particle velocity, determine the nature of the constant in Eq. (2.5). (2.5)

the buttons and labels we will be including in our app. This means that we need a place where the image can reside. In Interface Builder, you can place images on the Image Views. Scroll down in your Library until you see the Image View icon. Drag one onto your View frame, as shown in Figure 4 10.

package ucnyjca; public class UCConnection { private UCManagedConnection mc; public UCConnection(UCManagedConnection mc) { System.out.println("We are executing UCConnection"); this.mc = mc; } }

SOLUTION For simplicity, we consider motion in one spatial dimension. Now S = ds = dt 2 dx 2 = dt 1 dx 2 dt 2

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Hence, 1 1 v2 1 v2 2 Therefore S = dt 1 v 2 1 1 dt 1 v 2 = dt + dt v 2 2 2 Comparison of the second term in this expression with S0 = dt (1/ 2)mv 2 tells us that must be the mass of the particle. We can also determine the units of and deduce that it is the mass of the particle from dimensional analysis. First, what are the units of action Recall from your studies of quantum theory that the units of action from Planck s constant are mass times length squared per time: ML2 [ ]= T (2.6)

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