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// Demonstrate a generic method using System; // A class of array utilities // a generic class class ArrayUtils { Notice that this is not

// Compute the distance from the Earth to the sun, in inches using System; class Inches { static void Main() { long inches; long miles; miles = 93000000; // 93,000,000 miles to the sun // 5,280 feet in a mile, 12 inches in a foot inches = miles * 5280 * 12; ConsoleWriteLine("Distance to the sun: " + inches + " inches"); } }

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true if the argument is even and false otherwise Thus, it is compatible with the IsEven delegate declaration At this point, you might be wondering how the compiler knows the type of the data used in a lambda expression For example, in the lambda expression assigned to incr, how does the compiler know that count is an int The answer is that the compiler infers the type of the parameter and the expression s result type from the delegate type Thus, the lambda parameters and return value must be compatible with the parameter type(s) and return type of the delegate Although type inference is quite useful, in some cases, you might need to explicitly specify the type of a lambda parameter To do so, simply include the type name For example, here is another way to declare the incr delegate instance:

// Copy an array, inserting a new element in the process // This is a generic method A generic method public static bool CopyInsert<T>(T e, int idx, T[] src, T[] target) { // See if target array is big enough if(targetLength < srcLength+1) return false; // Copy src to target, inserting e at idx in the process for(int i=0, j=0; i < srcLength; i++, j++) { if(i == idx) { target[j] = e; j++; } target[j] = src[i]; }

Incr incr = (int count) => count + 2;

Notice now that count is explicitly declared as an int Also notice the use of parentheses They are now necessary (Parentheses can be omitted only when exactly one parameter is specified and no type specifier is used) Although the preceding two lambda expressions each used one parameter, lambda expressions can use any number, including zero When using more than one parameter you must enclose them within parentheses Here is an example that uses a lambda expression to determine if a value is within a specified range:

return true; } // } class GenMethDemo { static void Main() { int[] nums = { 1, 2, 3 }; int[] nums2 = new int[4]; // Display contents of nums ConsoleWrite("Contents of nums: "); foreach(int x in nums) ConsoleWrite(x + " "); ConsoleWriteLine(); // Operate on an int array ArrayUtilsCopyInsert(99, 2, nums, nums2); // Display contents of nums2 ConsoleWrite("Contents of nums2: "); foreach(int x in nums2) ConsoleWrite(x + " "); ConsoleWriteLine();

(low, high, val) => val >= low && val <= high;

// Now, use CopyInsert on an array of strings string[] strs = { "Generics", "are", "powerful"}; string[] strs2 = new string[4]; // Display contents of strs ConsoleWrite("Contents of strs: "); foreach(string s in strs) ConsoleWrite(s + " "); ConsoleWriteLine(); // Insert into a string array ArrayUtilsCopyInsert("in C#", 1, strs, strs2); // Display contents of strs2 ConsoleWrite("Contents of strs2: "); foreach(string s in strs2) ConsoleWrite(s + " "); ConsoleWriteLine();

Here is a delegate type that is compatible with this lambda expression:

delegate bool InRange(int lower, int upper, int v);

// This call is invalid because the first argument // is of type double, and the third and fourth arguments // have element types of int ArrayUtilsCopyInsert(001, 2, nums, nums2); } }

Thus, you could create an InRange delegate instance like this:

InRange rangeOK = (low, high, val) => val >= low && val <= high;

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