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The core element in MEMS generally consists of two principal components, namely, a sensing or actuating element and a signal transduction unit [6] Figure 86 illustrates the relationship between the components in a microsensor, microactuator and a microsystem A sensor is defined as a device that perceives useful information from a surrounding environment and provides one or more output variables to a measuring instrument On the other hand, an actuator is a device that creates a force to manipulate itself, other mechanical devices or the surrounding environment to perform some useful functions [2] Microsensors are built to detect thermal, mechanical, chemical, magnetic, radiant or electrical signals [4] The advantages of microsensors are that they are accurate when a minimal amount of the required sample substance is used On the other hand, microactuators function using the electrostatic principle, thermal forces and piezoelectric crystals Presently, microsystems consist of a microsensor, an actuator and a processing unit Microsystems have put forward the idea of systems-on-a-chip MEMS is an enabling technology which allows the development of smart products, augmenting the computational ability of microelectronics with the perception and control capabilities of microsensors and microactuators and expanding the space of possible designs and applications Microelectronic integrated circuits can be thought of as being the brain of a system, and MEMS augments this decision-making capability by lending it eyes and arms, to allow microsystems to sense and control the environment Sensors gather information from the environment through measuring mechanical, thermal, biological, chemical, optical, and magnetic phenomena The electronics then process the information derived from the sensors and through some decision-making capability direct the actuators to respond by moving, positioning, regulating, pumping and filtering, thereby controlling the environment for getting some desired outcome or purpose [7] Microelectromechanical systems (MEMS) can also be classified into passive electro/mechanical transducers and active electro/mechanical feedback to transducers Figure 87 shows a passive system in which the gain or the bandwidth is controlled by a preamplifier dynamic range There is no active transducer calibration, testing and control On the other hand, the active system in Figure 88 utilizes a front end gain or bandwidth control, and requires electromechanical system calibration, testing and control [8].

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Core losses are negligible a Determine the turns ratio b Determine the input voltage, current, and power and the ef ciency when this transformer is delivering 12 W to the 300- load at a frequency f = 10,000/2 Hz

low-voltage side Calculate a The number of turns on its high side b The turns ratio when it is used as a step-down transformer c The turns ratio when it is used as a step-up transformer

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turns, and the low-voltage side 50 turns When the high side is connected to a rated voltage of 120 V, 60 Hz, a rated load of 40 A is connected to the low side Calculate a The turns ratio b The secondary voltage (assuming no internal transformer impedance voltage drops) c The resistance of the load

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Microelectro-mechanical Systems (MEMS)

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1625 A transformer is to be used to match an 8loudspeaker to a 500- audio line What is the turns ratio of the transformer, and what are the voltages at the primary and secondary terminals when 10 W of audio power is delivered to the speaker Assume that the speaker is a resistive load and the transformer is ideal 1626 The high-voltage side of a step-down transformer has 800 turns, and the low-voltage side has 100 turns A voltage of 240 VAC is applied to the high side, and the load impedance is 3 (low side) Find a The secondary voltage and current b The primary current c The primary input impedance from the ratio of primary voltage and current d The primary input impedance

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Example 1611 using equation 1646 and the de nition of inductance given in equation 1630 You will rst compute the inductance of the magnetic circuit as a function of the reluctance, then compute the stored magnetic energy, and nally write the expression for the magnetic force given in equation 1646

simulation program (eg, using SimulinkTM ) that accounts for the fact that the solenoid inductance is not constant, but is a function of plunger position Compare graphically the current and force step responses of the constant-L simpli ed solenoid model to the step responses obtained in Example 1611

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in Problem 1626 when it is used as a step-up transformer 1628 A 2,300/240-V, 60-Hz, 46-kVA transformer is designed to have an induced emf of 25 V/turn Assuming an ideal transformer, nd a The number of high-side turns, Nh , and low-side turns, Nl b The rated current of the high-voltage side, Ih c The transformer ratio when the device is used as a step-up transformer

Fig 86: The functional relationship of a microsensor, microactuator and a microsystem [6]

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following parameters: Agap = 0001 m2 ; N = 500 turns; L = 002 m; = 0 = 4 10 7 (neglect the iron reluctance); k = 1000 N/m, R = 18 What is the minimum DC supply voltage, v, for which the relay will make contact when the electrical switch is closed

Section 4: Electromechanical Transducers 1629 For the electromagnet of Example 169:

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a Calculate the current required to keep the bar in place (Hint: The air gap becomes zero and the iron reluctance cannot be neglected) b If the bar is initially 01 m away from the electromagnet, what initial current would be required to lift the magnet

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