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software developers aware of the signi cance of errors and error reduction. The e ects of changes in the software process can be seen in the error data. Additionally, making the errors and error detection visible encourages testers and developers to keep error reduction as a goal. The error rate is the inverse of the inter-error time. That is, if errors occur every 2 days, then the instantaneous error rate is 0.5 errors/day. The current instantaneous error rate is a good estimate of the current error rate. If the faults that cause errors are not removed when the errors are found, then the cumulative error rate (the sum of all the errors found divided by the total time) is a good estimate of future error rates. Usually, most errors are corrected (the faults removed), and thus the error rates should go down and the inter-error times should be increasing. Plotting this data can show trends in the error rate (errors found per unit time). Fitting a straight line to the points is an e ective way to display the trend. The trend can be used to estimate future error rates. When the trend crosses the x-axis, the estimate of the error rate is zero, or there are no more errors. If the x-axis is number of errors, the value of the x-intercept can be used as an estimate of the total number of errors in the software. If the x-axis is the elapsed time of testing, the intercept is an estimate of the testing time necessary to remove all errors. The area under this latter line is an estimate of the number of errors originally in the software.

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EXAMPLE 13.3 Write expressions for the general value of (a) arcsin 1/2, (b) arccos ( 1), and (c) arctan ( 1).

(6.86)

Fig. 8-14.

Let H,(s) and HJz) be the system functions of the continuous-time and discrete-time systems, respectively (Fig. 6-51. Let Then from Eqs. (3.1) and (4.1) we have

(a) The principal value of arcsin 1/2 is /6, and a second value (not coterminal with the principal value) is 5 /6. The general value of arcsin 1/2 is given by /6 2n 5 /6 2n

10. Draw a state diagram for the data item reservation in the B&B problem (see Problem 4.3). See Fig. 8-15.

y (t ) = H,( jw ) elw'

(6.88)

Create reservation Not guaranteed Guarantee Guaranteed Guest arrive Cancel or forfeit guarantee Time elapsed Active Guest checkout

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where n is any positive or negative integer or zero. (b) The principal value is and there is no other value not coterminal with it. Thus, the general value is given by 2n , where n is a positive or negative integer or zero. (c) The principal value is /4, and a second value (not coterminal with the principal value) is 3 /4. Thus, the general value is given by /4 2n 3 /4 2n

Thus, the requirement y[n] = y(nTs) leads to the condition H,(jo) eJnwT,= Hd(ejwK) e~nwrs from which it follows that H,(jw)

Fig. 8-15.

= Hd(ejwT1)

11. Draw a state diagram for the dental o ce problem (see Problem 4.2). See Fig. 8-16.

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In terms of the Fourier transform, Eq. (6.89) can be expressed as H A 4 = HdW) R = wTs (6.90) Note that the frequency response Hd(R) of the discrete-time system is a periodic function of w (with period 27r/Ts), but that the frequency response H,(o) of the continuous-time system is not. Therefore, Eq. (6.90) or Eq. (6.89) cannot, in general, be true for every w . If the input x(t) is band-limited [Eq. (5.9411, then it is possible, in principle, to satisfy Eq. (6.89) for every w in the frequency range (-rr/Ts,r/Ts) (Fig. 6-6). However, from Eqs. (5.85) and (6.771, we see that Hc(w) is a rational function of w, whereas Hd(R) is a rational function of eJn (R = wT,). Therefore, Eq. (6.89) is impossible to satisfy. However, there are methods for determining a discrete-time system so as to satisfy Eq. (6.89) with reasonable accuracy for every w in the band of the input (Probs. 6.43 to 6.47).

7 /6 and 11 /6; from sin x 1 2( 1/2) ( 2)

" -T,

Fig. 8-16.

2n -

12. Draw a system diagram for the B&B system (see Problem 4.3). See Fig. 8-17.

/2, 2 sin x csc x 2(1) 1 7 /6 and 11 /6, 2 sin x csc x /2, 7 /6, and 11 /6.

Fig. 6-6

Fig. 8-17.

In this section we introduce the technique known as the discrete Fourier transform (DFT) for finite-length sequences. It should be noted that the DFT should not be confused with the Fourier transform.

/6 and 5 /6.

13. Draw a system diagram for the dental o ce system (see Problem 4.3). See Fig. 8-18.

outside the range 0 I n I N - 1

The DFT of x [ n ] ,denoted as X [ k ] ,is defined by X [ k ]=

Fig. 8-18.

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